x^(2/3)-10x^(1/3)+25

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Solution for x^(2/3)-10x^(1/3)+25 equation: 


x in (-oo:+oo)

x^(2/3)-(10*x^(1/3))+25 = 0

x^(2/3)-10*x^(1/3)+25 = 0

t_1 = x^(1/3)

1*t_1^2-10*t_1^1+25 = 0

t_1^2-10*t_1+25 = 0

DELTA = (-10)^2-(1*4*25)

DELTA = 0

t_1 = 10/(1*2)

t_1 = 5 or t_1 = 5

t_1 = 5

x^(1/3)-5 = 0

1*x^(1/3) = 5 // : 1

x^(1/3) = 5

x^(1/3) = 5 // ^ 3

x = 125

t_1 = 5

x^(1/3)-5 = 0

1*x^(1/3) = 5 // : 1

x^(1/3) = 5

x^(1/3) = 5 // ^ 3

x = 125

x in { 125, 125 }

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